Eureka Math Grade 5 Module 1 Lesson 1 Answer Key (2024)

Engage NY Eureka Math 5th Grade Module 1 Lesson 1 Answer Key

Eureka Math Grade 5 Module 1 Lesson 1 Sprint Answer Key

A
Multiply by 10

Answer:-

Question 1.
12 × 10 =

Answer:-
12 x 10 = 120
Explanation:-
By multiplying 12 x 10 we will get the result as 120.

Question 2.
14 × 10 =

Answer:-
14 x 10 = 120
Explanation:-
By multiplying 14 x 10 we will get the result as 140.

Question 3.
15 × 10 =

Answer:-
15 x 10 = 150
Explanation:-
By multiplying 15 x 10 we will get the result as 150.

Question 4.
17 × 10 =

Answer:-
17 x 10 = 170
Explanation:-
By multiplying 17 x 10 we will get the result as 170.

Question 5.
81 × 10 =

Answer:-
81 x 10 = 810
Explanation:-
By multiplying 81 x 10 we will get the result as 810.

Question 6.
10 × 81 =

Answer:-
10 x 81 = 810
Explanation:-
By multiplying 10 x 81 we will get the result as 810.

Question 7.
21 × 10 =

Answer:-
21 x 10 = 210
Explanation:-
By multiplying 21 x 10 we will get the result as 210.

Question 8.
22 × 10 =

Answer:-
22 x 10 = 220
Explanation:-
By multiplying 22 x 10 we will get the result as 220.

Question 9.
23 × 10 =

Answer:-
23 x 10 = 230
Explanation:-
By multiplying 23 x 10 we will get the result as 230.

Question 10.
29 × 10 =

Answer:-
29 x 10 = 290
Explanation:-
By multiplying 29 x 10 we will get the result as 290.

Question 11.
92 × 10 =

Answer:-
92 x 10 = 920
Explanation:-
By multiplying 92 x 10 we will get the result as 920.

Question 12.
10 × 92 =

Answer:-
10 x 92 = 920
Explanation:-
By multiplying 10 x 92 we will get the result as 920.

Question 13.
18 × 10 =

Answer:-
18 x 10 = 180
Explanation:-
By multiplying 18 x 10 we will get the result as 180.

Question 14.
19 × 10 =

Answer:-
19 x 10 = 190
Explanation:-
By multiplying 19 x 10 we will get the result as 190.

Question 15.
20 × 10 =

Answer:-
20 x 10 = 200
Explanation:-
By multiplying 20 x 10 we will get the result as 200.

Question 16.
30 × 10 =

Answer:-
12 x 10 = 120
Explanation:-
By multiplying 12 x 10 we will get the result as 120.

Question 17.
40 × 10 =

Answer:-
40 x 10 = 400
Explanation:-
By multiplying 40 x 10 we will get the result as 400.

Question 18.
80 × 10 =

Answer:-
80 x 10 = 800
Explanation:-
By multiplying 80 x 10 we will get the result as 800.

Question 19.
10 × 80 =

Answer:-
10 x 80 = 800
Explanation:-
By multiplying 10 x 80 we will get the result as 800.

Question 20.
10 × 50 =

Answer:-
10 x 50 = 500
Explanation:-
By multiplying 10 x 50 we will get the result as 500.

Question 21.
10 × 90 =

Answer:-
10 x 90 = 900
Explanation:-
By multiplying 10 x 90 we will get the result as 900.

Question 22.
10 × 70 =

Answer:-
10 x 70 = 700
Explanation:-
By multiplying 10 x 70 we will get the result as 700.

Question 23.
34 × 10 =

Answer:-
34 x 10 = 340
Explanation:-
By multiplying 34 x 10 we will get the result as 340.

Question 24.
134 × 10 =

Answer:-
134 x 10 = 1340
Explanation:-
By multiplying 134 x 10 we will get the result as 1340.

Question 25.
234 × 10 =

Answer:-
234 x 10 = 2340
Explanation:-
By multiplying 234 x 10 we will get the result as 2340.

Eureka Math Grade 5 Module 1 Lesson 1 Problem Set Answer Key

Question 1.
Use the place value chart and arrows to show how the value of the each digit changes. The first one has been done for you.
a. 3.452 × 10 = 34.52

b. 3.452 × 100 = _________

Answer:-
3.452 × 100 = 345.2

c. 3.452 × 1,000 = ________

Answer:-
3.452 × 1,000 = 3452

d. Explain how and why the value of the 5 changed in (a), (b), and (c).
Answer:- The value of 5 in (a) is tenth place, the value of 5 has changed when its multiplying with 100 and placed in 100th value.
Likewise, when the 5 is multiplying with 1000 its changes its place to 1000. When we multiply any number with 10 or 100 or 1000
it increases its value like if the number is in right side the decimal it has less value and left side of the decimal it has more value.

Question 2.
Use the place value chart and arrows to show how the value of each digit changes. The first one has been done for you.
a. 345 ÷ 10 = 34.5

b. 345 ÷ 100 = ____________

Answer:-
345 ÷ 100 = 3.45

c. 345 ÷ 1,000 = _____________

Answer:-
345 ÷ 1,000 = 0.345

d. Explain how and why the value of the 4 changed in the quotients in (a), (b), and (c).
Answer:- The value of 4 in (a) is tenth position when we dividing it by 100 it changes its quotient and becomes less value because
when the number is in right of the decimal it has less value. Likewise, when the value is dividing it with 1000 its value becomes 0. something. When we divide any number with any number its gradually decreases and distribute its value to the dividing number.

Question 3.
A manufacturer made 7,234 boxes of coffee stirrers. Each box contains 1,000 stirrers. How many stirrers did they make? Explain your thinking, and include a statement of the solution.

Answer:- There are totally 7234 boxes and in each box they contains 1000 stirrers. That means we have to multiply 7234 boxes with
1000 then we get the answer. In the same way, I have elaborated my answer.

The No. of boxes of coffee stirrers made by Manufacturer = 7234
Each box contains coffee stirrers = 1000
Total Number of coffee stirrers = No. of boxes X Each box contains coffee stirrers
= 7234 X 1000
= 7,23,4000
Therefore, The total No. of coffee stirrers are 7,23,4000.

Question 4.
A student used his place value chart to show a number. After the teacher instructed him to multiply his number by 10, the chart showed 3,200.4. Draw a picture of what the place value chart looked like at first.

Explain how you decided what to draw on your place value chart. Be sure to include your reasoning about how the value of each digit was affected by the multiplication. Use words, pictures, or numbers.
Answer:- The teacher gave 3200.4 and said to multiply with 10. If any number has to multiply with 10 which has decimal value and the value get higher
Actual decimal number has least value so its get higher value when multiplied by 10. Before the value mutliplied by 10 is show below:
320.04 x 10 = 3200.4

Question 5.
A microscope has a setting that magnifies an object so that it appears 100 times as large when viewed through the eyepiece. If a tiny insect is 0.095 cm long, how long will the insect appear in centimeters through the microscope? Explain how you know.
Answer:- A microscope has a setting that magnifies an object so that it appears 100 times that means we have to multiply the insect size with 100.
Insect size is 0.095 x 100 = 9.5 which means the insect appears 9.5 times larger from its actual size. 9.5 cm of size the insect represents its size through
microscope.

Eureka Math Grade 5 Module 1 Lesson 1 Exit Ticket Answer Key

Use the place value chart and arrows to show how the value of each digit changes.
a. 6.671 × 100 = ____________

Answer:-
6.671 × 100 = 667.1

b. 684 ÷ 1,000 = ____________

Answer:-
684 ÷ 1,000 = 0.684

Eureka Math Grade 5 Module 1 Lesson 1 Homework Answer Key

Question 1.
Use the place value chart and arrows to show how the value of each digit changes. The first one has been done for you.
a. 4.582 × 10 = 45.82

b. 7.281 × 100 = ____________

Answer:-
7.281 × 100 = 72.81

c. 9.254 × 1,000 = ____________

Answer:-
9.254 × 1,000 = 9254

d. Explain how and why the value of the 2 changed in (a), (b), and (c).
Answer:- The value of 2 in (a) is tenth place, the value of 2 has changed when its multiplying with 100 and placed in 100th value.
Likewise, when the 2 is multiplying with 1000 its changes its place to 1000. When we multiply any number with 10 or 100 or 1000
it increases its value like if the number is in right side the decimal it has less value and left side of the decimal it has more value.

Question 2.
Use the place value chart and arrows to show how the value of each digit changes. The first one has been done for you.
a. 2.46 ÷ 10 = 0.246

b. 678 ÷ 100 = ____________

Answer:-
678 ÷ 100 = 6.78

c. 67 ÷ 1,000 = ____________

Answer:-
67 ÷ 1,000 = 0.067

d. Explain how and why the value of the 6 changed in the quotients in (a), (b), and (c).
Answer:- The value of 6 in (a) is tenth position when we dividing it by 100 it changes its quotient and becomes less value because
when the number is in right of the decimal it has less value. Likewise, when the value is dividing it with 1000 its value becomes 0. something. When we divide any number with any number its gradually decreases and distribute its value to the dividing number.

Question 3.
Researchers counted 8,912 monarch butterflies on one branch of a tree at a site in Mexico. They estimated that the total number of butterflies at the site was 1,000 times as large. About how many butterflies were at the site in all? Explain your thinking, and include a statement of the solution.
Answer:- There are 8912 monarch butterflies on one branch of a tree and they have estimated total was 1000 times large so we have multiplied that with 1000 then will get the total no. of butterflies of all branches of a tree

Monarch Butterflies of a tree in Mexico = 8912
The Estimated butterflies at the Site = 1000
Therefore, The total No. of butterflies at the site = Monarch Butterflies of a tree in Mexico x The Estimated butterflies at the Site
= 8912 x 1000
= 89,12,000

Question 4.
A student used his place value chart to show a number. After the teacher instructed him to divide his number by 100, the chart showed 28.003. Draw a picture of what the place value chart looked like at first.

Explain how you decided what to draw on your place value chart. Be sure to include reasoning about how the value of each digit was affected by the division.
Answer:- The teacher gave 2800.3 and said to divide with 100. If any number has to divide with 100 which has decimal value and the value get lower
Actual decimal number has value highest so its get lowest value when divide by 100. Before the value divided by 100 is show below:
2800.3 ÷ 100 = 28.003

Question 5.
On a map, the perimeter of a park is 0.251 meters. The actual perimeter of the park is 1,000 times as large. What is the actual perimeter of the park? Explain how you know using a place value chart.
Answer:-
The perimeter on the map is 0.251 and the actual perimeter is 1000 times larger i.e., 0.251 x 1000 = 251
So the actual perimeter of the park is 251. We have multiplied the number with actual size of the perimeter.

Eureka Math Grade 5 Module 1 Lesson 1 Answer Key (2024)

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Not all Eureka Math lessons are formatted in the same way, but lessons in the same grade-band all follow a similar structure. Lessons in A Story of Units (PK-5) are written for a 60-minute class period, except for Pre-K lessons, which are 25 minutes, and K lessons, which are 50 minutes*.

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Fluency Activities. Every Eureka math lesson comes with fluency activities. ...
Concept Development. Concept development is your lesson or instructional focus for the day. ...
Debrief. ...
Additional Websites. ...
Small Math Groups. ...
Math Centers.

Nov 28, 2022

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Each lesson in A Story of Units is comprised of four critical components: fluency practice, concept development (including the problem set), application problem, and student debrief (including the Exit Ticket).

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Eureka Math Grade 5 Module 1 Lesson 1 Answer Key (2024)

Engage NY Eureka Math 5th Grade Module 1 Lesson 1 Answer Key

Eureka Math Grade 5 Module 1 Lesson 1 Sprint Answer Key

Eureka Math Grade 5 Module 1 Lesson 1 Problem Set Answer Key

Eureka Math Grade 5 Module 1 Lesson 1 Exit Ticket Answer Key

Eureka Math Grade 5 Module 1 Lesson 1 Homework Answer Key

FAQs

What grade does Eureka math go up to? ›

How long should a Eureka Math lesson be? ›

References